Hello
I am trying to figure out the steps I need to take to answer this question and I'm having a tough time with it.
If I have 100 grams of starter and I know it is an 80% hydration starter, how do I determine how much flour is in the starter?
I actually know the answer (54g flour 44g water), I just dont know how to arrive at it for myself.
I am looking for the steps to take so I can do it for myself.
If anyone knows how to arrive at the answer it would be much appreciated.
Many thanks
Peter
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The desired weight is 100-gram
Assume % flour is 100%
Water % is 80
Total % is 180
Conversion factor is 100 / 180 = 0.555556 (weight / total percent)
Multiply each of the ingredients % by conversion factor.
Flour = 100 * 0.555556 = 55.5556 gram
Water = 80 * 0.555556 = 44.4444 gram
Round off the results.
Cheers,
Gavin
The long way:
Let the weight of flour in your starter be 1x.
Then the weight of water in your starter is 0.8x.
We can set up the equation: 1x + 0.8x = 100.
Combining like terms, we have: 1.8x = 100.
To solve for x, we divide both sides of the equation by 1.8:
x = 100/1.8.
Therefore, x ≈ 55, which represents the weight of flour in your starter.
The shortcut:
Alternatively, you can use the following formula:
divide the weight of the starter
by
(1 + the ratio of water to flour in the starter, i.e., the starter hydration)
👇👇👇
100/(1+0.8) = 55
Yippee
80% hydration can also be expressed as 4:5 (4 parts water to 5 parts flour by weight).
4 + 5 = 9
100 [starter] / 9 = 11.1111 (go to 4 decimal places)
Then multiply each part of the ratio by 11.1111....
4 [water] x 11.1111 = 44.4444
5 [flour] x 11.1111 = 55.5555
So the answer would be 44.4g water + 55.5g flour to be exact but round up or down to the nearest whole number.
Hi everyone
Thanks so much for the practical answers.
This is handy for me.
Peter